28x^2+392x-89600=0

Solution for 28x^2+392x-89600=0 equation:

28x^2+392x-89600=0

a = 28; b = 392; c = -89600;
Δ = b2-4ac
Δ = 3922-4·28·(-89600)
Δ = 10188864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10188864}=3192$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(392)-3192}{2*28}=\frac{-3584}{56}
=-64
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(392)+3192}{2*28}=\frac{2800}{56}
=50
$